GCSE Algebra exam-style questions
Use Clevolab for GCSE exam-style practice in algebra. This page shows what the topic covers, what skills the current set targets, and a few real examples from the reviewed question bank.
About this topic
Clevolab treats algebra as repeated practice with explanation, not just answer checking. This page is designed to make the topic legible before you open the app.
The current GCSE set covers equations, inequalities, sequences, quadratics, expressions, and algebraic manipulation. 58 reviewed questions currently published for this page.
What you can practise
- Simplifying expressions
- Solving equations and inequalities
- Factorising and expanding
- Sequences and nth-term reasoning
- Quadratic structure
Real sample questions from the current set
These examples come from the reviewed questions currently stored for this topic. They are here so the page shows the actual flavour of Clevolab, not just a summary.
Sample question
Solve $\dfrac{7}{x} = 2$ for $x \ne 0$.
- A$x = \dfrac{7}{2}$Correct answer
- B$x = 2$Answer option
- C$x = \dfrac{2}{7}$Answer option
- D$x = -\dfrac{7}{2}$Answer option
Why this answer is right
Multiply both sides by $x$ then divide by 2: $7=2x$ so $x=\dfrac{7}{2}$.
Clear the denominator. Multiply both sides by $x$: $$7 = 2x.$$ Divide by $2$: $$x = \frac{7}{2}.$$ Inverting to $2/7$ mistakes the operation; adding signs without reason gives $-7/2$.
Sample question
Simplify $\dfrac{x + 2}{x} + \dfrac{3}{x}$ for $x \ne 0$.
- A$\dfrac{x + 5}{x}$Correct answer
- B$\dfrac{x + 2}{x^2} + \dfrac{3}{x}$Answer option
- C$1 + \dfrac{5}{x}$Answer option
- D$\dfrac{5}{x^2}$Answer option
Why this answer is right
Common denominator $x$: add numerators to get $\dfrac{x + 2 + 3}{x} = \dfrac{x + 5}{x}$.
Combine over the common denominator $x$. Compute $$\frac{x+2}{x} + \frac{3}{x} = \frac{(x+2)+3}{x}.$$ This simplifies to $$\frac{x+5}{x}.$$ It is also equal to $$1 + \frac{5}{x}.$$ Squaring denominators would be incorrect.
Sample question
Find the 10th term of the sequence with nth term $4n - 1$.
- A$39$Correct answer
- B$41$Answer option
- C$38$Answer option
- D$-1$Answer option
Why this answer is right
Substitute $n=10$ into $4n - 1$: $4\cdot 10 - 1 = 39$.
Use the given formula directly. Compute $$4n - 1\text{ at }n=10.$$ This gives $$4\cdot 10 - 1 = 40 - 1 = 39.$$ Values like $41$ or $38$ come from adding or subtracting instead of subtracting 1 after multiplying.
How this page fits into Clevolab
Clevolab is broader than any one exam mode. GCSE and A-level pages are useful entry points, while the wider project is about sharpening understanding through repeated topic practice.